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Discrete space : ウィキペディア英語版
Discrete space

In topology, a discrete space is a particularly simple example of a topological space or similar structure, one in which the points form a ''discontinuous sequence'', meaning they are ''isolated'' from each other in a certain sense. The discrete topology is the finest topology that can be given on a set, i.e., it defines all subsets as open sets. In particular, each singleton is an open set in the discrete topology.
== Definitions ==
Given a set ''X'':
* the discrete topology on ''X'' is defined by letting every subset of ''X'' be open (and hence also closed), and ''X'' is a discrete topological space if it is equipped with its discrete topology;
* the discrete uniformity on ''X'' is defined by letting every superset of the diagonal in ''X'' × ''X'' be an entourage, and ''X'' is a discrete uniform space if it is equipped with its discrete uniformity.
* the discrete metric \rho on ''X'' is defined by
:\rho(x,y) =
\left\\ x\neq y , \\
0 &\mbox\ x = y
\end\right.

for any x,y \in X. In this case (X,\rho) is called a discrete metric space or a space of isolated points.
* a set ''S'' is discrete in a metric space (X,d), for S \subseteq X, if for every x \in S, there exists some \delta >0 (depending on x) such that d(x,y) >\delta for all y \in S\setminus\; such a set consists of isolated points. A set ''S'' is uniformly discrete in the metric space (X,d), for S \subseteq X, if there exists ''ε'' > 0 such that for any two distinct x, y \in S, d(x, y) > ''ε''.
A metric space (E,d) is said to be ''uniformly discrete'' if there exists a "packing radius" r>0 such that, for any x,y \in E, one has either x=y or d(x,y)>r. The topology underlying a metric space can be discrete, without the metric being uniformly discrete: for example the usual metric on the set of real numbers.
Let X = , consider this set using the usual metric on the real numbers. Then, X is a discrete space, since for each point 1/2n, we can surround it with the interval (1/2n - ɛ, 1/2n + ɛ), where ɛ = 1/2(1/2n - 1/2n+1) = 1/2n+2. The intersection (1/2n - ɛ, 1/2n + ɛ) ∩ is just the singleton . Since the intersection of two open sets is open, and singletons are open, it follows that X is a discrete space.
However, X cannot be uniformly discrete. To see why, suppose there exists an r>0 such that d(x,y)>r whenever x≠y. It suffices to show that there are at least two points x and y in X that are closer to each other than r. Since the distance between adjacent points 1/2n and 1/2n+1 is 1/2n+1, we need to find an n that satisfies this inequality:

1/2^ < r


1 < r2^


1/r < 2^


\log_2(1/r) < n+1


-\log_2(r) < n+1


-1 - \log_2(r) < n

Since there is always an n bigger than any given real number, it follows that there will always be at least two points in X that are closer to each other than any positive r, therefore X is not uniformly discrete.
...

抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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